44g^2-45g+1=0

Solution for 44g^2-45g+1=0 equation:

44g^2-45g+1=0

a = 44; b = -45; c = +1;
Δ = b2-4ac
Δ = -452-4·44·1
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-43}{2*44}=\frac{2}{88}
=1/44
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+43}{2*44}=\frac{88}{88}
=1
$